$\cot\left(x\right)\sec\left(x\right)=\csc\left(x\right)$

Step-by-step Solution

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Final answer to the problem

true

Step-by-step Solution

How should I solve this problem?

  • Esprimere tutto in seno e coseno
  • Dimostrare dal LHS (lato sinistro)
  • Dimostrare da RHS (lato destro)
  • Equazione differenziale esatta
  • Equazione differenziale lineare
  • Equazione differenziale separabile
  • Equazione differenziale omogenea
  • Prodotto di binomi con termine comune
  • Metodo FOIL
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Can't find a method? Tell us so we can add it.

I. Express the LHS in terms of sine and cosine and simplify

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Start from the LHS (left-hand side)

$\cot\left(x\right)\sec\left(x\right)$
2

Apply the trigonometric identity: $\cot\left(\theta \right)$$=\frac{\cos\left(\theta \right)}{\sin\left(\theta \right)}$

$\frac{\cos\left(x\right)}{\sin\left(x\right)}\sec\left(x\right)$
Why is cot(x) = cos(x)/sin(x) ?
3

Apply the trigonometric identity: $\sec\left(\theta \right)$$=\frac{1}{\cos\left(\theta \right)}$

$\frac{\cos\left(x\right)}{\sin\left(x\right)}\frac{1}{\cos\left(x\right)}$
4

Apply the formula: $\frac{a}{b}\frac{c}{f}$$=\frac{ac}{bf}$, where $a=\cos\left(x\right)$, $b=\sin\left(x\right)$, $c=1$, $a/b=\frac{\cos\left(x\right)}{\sin\left(x\right)}$, $f=\cos\left(x\right)$, $c/f=\frac{1}{\cos\left(x\right)}$ and $a/bc/f=\frac{\cos\left(x\right)}{\sin\left(x\right)}\frac{1}{\cos\left(x\right)}$

$\frac{\cos\left(x\right)}{\sin\left(x\right)\cos\left(x\right)}$
5

Apply the formula: $\frac{a}{a}$$=1$, where $a=\cos\left(x\right)$ and $a/a=\frac{\cos\left(x\right)}{\sin\left(x\right)\cos\left(x\right)}$

$\frac{1}{\sin\left(x\right)}$

II. Express the RHS in terms of sine and cosine and simplify

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Start from the RHS (right-hand side)

$\csc\left(x\right)$
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Apply the trigonometric identity: $\csc\left(\theta \right)$$=\frac{1}{\sin\left(\theta \right)}$

$\frac{1}{\sin\left(x\right)}$

III. Choose what side of the identity are we going to work on

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To prove an identity, we usually begin to work on the side of the equality that seems to be more complicated, or the side that is not expressed in terms of sine and cosine. In this problem, we will choose to work on the left side $\frac{1}{\sin\left(x\right)}$ to reach the right side $\frac{1}{\sin\left(x\right)}$

$\frac{1}{\sin\left(x\right)}=\frac{1}{\sin\left(x\right)}$

IV. Check if we arrived at the expression we wanted to prove

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Since we have reached the expression of our goal, we have proven the identity

true

Final answer to the problem

true

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