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Apply the formula: $\log_{b}\left(x\right)$$=\log_{b}\left(pfg\left(x\right)\right)$, where $b=16$ and $x=4$
Apply the formula: $\log_{b}\left(x^a\right)$$=a\log_{b}\left(x\right)$, where $a=2$, $b=16$ and $x=2$