Solve the inequality $x-3\leq 5$

$\frac{d}{dx}\left(x^3-3x^2y+2xy^2=12\right)$

$\frac{d}{dx}\left(y^2\:-\:2y=x\right)$

$\frac{d}{dx}\left(x^3+y^3=6xy\right)$

$\frac{d}{dx}\left(\frac{x+y}{x-y}=x\right)$

$\frac{d}{dx}\left(x^2+xy-y^2=4\right)$

$\frac{d}{dx}\left(x^2-xy+y^2=3\right)$

$\frac{d}{dx}\left(2x^2+3y^2-4xy=36\right)$