$y^{\prime}=\frac{1-y}{1+x}$

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Impara online a risolvere i problemi di equazioni differenziali passo dopo passo.

$\frac{dy}{dx}=\frac{1-y}{1+x}$

Impara online a risolvere i problemi di equazioni differenziali passo dopo passo. y^'=(1-y)/(1+x). Rewrite the differential equation using Leibniz notation. Rewrite the differential equation in the standard form M(x,y)dx+N(x,y)dy=0. The differential equation 1+xdy-\left(1-y\right)dx=0 is exact, since it is written in the standard form M(x,y)dx+N(x,y)dy=0, where M(x,y) and N(x,y) are the partial derivatives of a two-variable function f(x,y) and they satisfy the test for exactness: \displaystyle\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}. In other words, their second partial derivatives are equal. The general solution of the differential equation is of the form f(x,y)=C. Using the test for exactness, we check that the differential equation is exact.