Esercizio
$\:\frac{2x^4+5x^3+7x^2-3x+8}{x+3}$
Soluzione passo-passo
1
Dividere $2x^4+5x^3+7x^2-3x+8$ per $x+3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+3;}{\phantom{;}2x^{3}-x^{2}+10x\phantom{;}-33\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+3\overline{\smash{)}\phantom{;}2x^{4}+5x^{3}+7x^{2}-3x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+3;}\underline{-2x^{4}-6x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}-6x^{3};}-x^{3}+7x^{2}-3x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n;}\underline{\phantom{;}x^{3}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}x^{3}+3x^{2}-;x^n;}\phantom{;}10x^{2}-3x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n;}\underline{-10x^{2}-30x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-10x^{2}-30x\phantom{;}-;x^n-;x^n;}-33x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n-;x^n;}\underline{\phantom{;}33x\phantom{;}+99\phantom{;}\phantom{;}}\\\phantom{;;;\phantom{;}33x\phantom{;}+99\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}107\phantom{;}\phantom{;}\\\end{array}$
$2x^{3}-x^{2}+10x-33+\frac{107}{x+3}$
Risposta finale al problema
$2x^{3}-x^{2}+10x-33+\frac{107}{x+3}$