Esercizio
$\frac{\frac{1}{27}x^{12}-\frac{8}{27}y^6}{\frac{1}{3}x^4-\frac{2}{3}y^2}$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. (1/27x^12-8/27y^6)/(1/3x^4-2/3y^2). Applicare la formula: a+b=\left(\sqrt[3]{a}+\sqrt[3]{\left|b\right|}\right)\left(\sqrt[3]{a^{2}}-\sqrt[3]{a}\sqrt[3]{\left|b\right|}+\sqrt[3]{\left|b\right|^{2}}\right), dove a=\frac{1}{27}x^{12} e b=-\frac{8}{27}y^6. Applicare la formula: \left(ab\right)^n=a^nb^n, dove a=\frac{1}{27}, b=x^{12} e n=\frac{1}{3}. Applicare la formula: a^b=a^b, dove a=\frac{1}{27}, b=\frac{1}{3} e a^b=\sqrt[3]{\frac{1}{27}}. Applicare la formula: \left(ab\right)^n=a^nb^n, dove a=\frac{8}{27}, b=y^6 e n=\frac{1}{3}.
(1/27x^12-8/27y^6)/(1/3x^4-2/3y^2)
Risposta finale al problema
$\frac{\left(\frac{1}{3}x^{4}+\frac{2}{3}y^{2}\right)\left(\frac{1}{9}x^{8}-\frac{2}{9}x^{4}y^{2}+\frac{4}{9}y^{4}\right)}{\frac{1}{3}x^4-\frac{2}{3}y^2}$