Applicare la formula: $\frac{\frac{a}{b}}{c}$$=\frac{a}{bc}$, dove $a=10h$, $b=x^2-5h-hx+25-10x$, $c=h$, $a/b/c=\frac{\frac{10h}{x^2-5h-hx+25-10x}}{h}$ e $a/b=\frac{10h}{x^2-5h-hx+25-10x}$

Applicare la formula: $\frac{a}{a}$$=1$, dove $a=h$ e $a/a=\frac{10h}{\left(x^2-5h-hx+25-10x\right)h}$