Impara online a risolvere i problemi di passo dopo passo. (6/((x+y)^2+1)+-6/(x^2+1))/y. Applicare la formula: a+\frac{b}{c}=\frac{b+ac}{c}, dove a=\frac{6}{\left(x+y\right)^2+1}, b=-6, c=x^2+1, a+b/c=\frac{6}{\left(x+y\right)^2+1}+\frac{-6}{x^2+1} e b/c=\frac{-6}{x^2+1}. Applicare la formula: a+\frac{b}{c}=\frac{b+ac}{c}, dove a=-6, b=6\left(x^2+1\right), c=\left(x+y\right)^2+1, a+b/c=-6+\frac{6\left(x^2+1\right)}{\left(x+y\right)^2+1} e b/c=\frac{6\left(x^2+1\right)}{\left(x+y\right)^2+1}. Applicare la formula: \frac{\frac{a}{b}}{c}=\frac{a}{bc}, dove a=\frac{6\left(x^2+1\right)-6\left(\left(x+y\right)^2+1\right)}{\left(x+y\right)^2+1}, b=x^2+1, c=y, a/b/c=\frac{\frac{\frac{6\left(x^2+1\right)-6\left(\left(x+y\right)^2+1\right)}{\left(x+y\right)^2+1}}{x^2+1}}{y} e a/b=\frac{\frac{6\left(x^2+1\right)-6\left(\left(x+y\right)^2+1\right)}{\left(x+y\right)^2+1}}{x^2+1}. Applicare la formula: \frac{\frac{a}{b}}{c}=\frac{a}{bc}, dove a=6\left(x^2+1\right)-6\left(\left(x+y\right)^2+1\right), b=\left(x+y\right)^2+1, c=\left(x^2+1\right)y, a/b/c=\frac{\frac{6\left(x^2+1\right)-6\left(\left(x+y\right)^2+1\right)}{\left(x+y\right)^2+1}}{\left(x^2+1\right)y} e a/b=\frac{6\left(x^2+1\right)-6\left(\left(x+y\right)^2+1\right)}{\left(x+y\right)^2+1}.

(6/((x+y)^2+1)+-6/(x^2+1))/y