Applicare la formula: $\frac{a^m}{a^n}$$=a^{\left(m-n\right)}$, dove $a^n={\left(-2\right)}^3$, $a^m={\left(-2\right)}^8$, $a=-2$, $a^m/a^n=\frac{{\left(-2\right)}^8}{{\left(-2\right)}^3}$, $m=8$ e $n=3$

Applicare la formula: $a^b$$=a^b$, dove $a=-2$, $b=5$ e $a^b={\left(-2\right)}^{5}$