Esercizio
$\frac{\left(-2x+4x^3+6+2x^4-7x^2\right)}{\left(2x+x^2-2\right)}$
Soluzione passo-passo
1
Dividere $-2x+4x^3+6+2x^4-7x^2$ per $2x+x^2-2$
$\begin{array}{l}\phantom{\phantom{;}x^{2}+2x\phantom{;}-2;}{\phantom{;}2x^{2}\phantom{-;x^n}-3\phantom{;}\phantom{;}}\\\phantom{;}x^{2}+2x\phantom{;}-2\overline{\smash{)}\phantom{;}2x^{4}+4x^{3}-7x^{2}-2x\phantom{;}+6\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}+2x\phantom{;}-2;}\underline{-2x^{4}-4x^{3}+4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}-4x^{3}+4x^{2};}-3x^{2}-2x\phantom{;}+6\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}+2x\phantom{;}-2-;x^n;}\underline{\phantom{;}3x^{2}+6x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}3x^{2}+6x\phantom{;}-6\phantom{;}\phantom{;}-;x^n;}\phantom{;}4x\phantom{;}\phantom{-;x^n}\\\end{array}$
$2x^{2}-3+\frac{4x}{2x+x^2-2}$
Risposta finale al problema
$2x^{2}-3+\frac{4x}{2x+x^2-2}$