Esercizio
$\frac{\left(3x^4-3x^2+x-5\right)}{\left(x^2+3\right)}$
Soluzione passo-passo
1
Dividere $3x^4-3x^2+x-5$ per $x^2+3$
$\begin{array}{l}\phantom{\phantom{;}x^{2}+3;}{\phantom{;}3x^{2}\phantom{-;x^n}-12\phantom{;}\phantom{;}}\\\phantom{;}x^{2}+3\overline{\smash{)}\phantom{;}3x^{4}\phantom{-;x^n}-3x^{2}+x\phantom{;}-5\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}+3;}\underline{-3x^{4}\phantom{-;x^n}-9x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3x^{4}-9x^{2};}-12x^{2}+x\phantom{;}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}+3-;x^n;}\underline{\phantom{;}12x^{2}\phantom{-;x^n}+36\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}12x^{2}+36\phantom{;}\phantom{;}-;x^n;}\phantom{;}x\phantom{;}+31\phantom{;}\phantom{;}\\\end{array}$
$3x^{2}-12+\frac{x+31}{x^2+3}$
Risposta finale al problema
$3x^{2}-12+\frac{x+31}{x^2+3}$