Esercizio
$\frac{\left(3y^3+2y^2-7y+2\right)}{3y-1}$
Soluzione passo-passo
1
Dividere $3y^3+2y^2-7y+2$ per $3y-1$
$\begin{array}{l}\phantom{\phantom{;}3y\phantom{;}-1;}{\phantom{;}y^{2}+y\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{;}3y\phantom{;}-1\overline{\smash{)}\phantom{;}3y^{3}+2y^{2}-7y\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}3y\phantom{;}-1;}\underline{-3y^{3}+y^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3y^{3}+y^{2};}\phantom{;}3y^{2}-7y\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}3y\phantom{;}-1-;x^n;}\underline{-3y^{2}+y\phantom{;}\phantom{-;x^n}}\\\phantom{;-3y^{2}+y\phantom{;}-;x^n;}-6y\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}3y\phantom{;}-1-;x^n-;x^n;}\underline{\phantom{;}6y\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}6y\phantom{;}-2\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$y^{2}+y-2$