Esercizio
$\frac{\left(4x^3-3x^2+2x-1\right)}{\left(x^2-3\right)}$
Soluzione passo-passo
1
Dividere $4x^3-3x^2+2x-1$ per $x^2-3$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-3;}{\phantom{;}4x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-3\overline{\smash{)}\phantom{;}4x^{3}-3x^{2}+2x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-3;}\underline{-4x^{3}\phantom{-;x^n}+12x\phantom{;}\phantom{-;x^n}}\\\phantom{-4x^{3}+12x\phantom{;};}-3x^{2}+14x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3-;x^n;}\underline{\phantom{;}3x^{2}\phantom{-;x^n}-9\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}3x^{2}-9\phantom{;}\phantom{;}-;x^n;}\phantom{;}14x\phantom{;}-10\phantom{;}\phantom{;}\\\end{array}$
$4x-3+\frac{14x-10}{x^2-3}$
Risposta finale al problema
$4x-3+\frac{14x-10}{x^2-3}$