Esercizio
$\frac{\left(6x^3+3x^2-10x-12\right)}{2x-3}$
Soluzione passo-passo
1
Dividere $6x^3+3x^2-10x-12$ per $2x-3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-3;}{\phantom{;}3x^{2}+6x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-3\overline{\smash{)}\phantom{;}6x^{3}+3x^{2}-10x\phantom{;}-12\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-3;}\underline{-6x^{3}+9x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-6x^{3}+9x^{2};}\phantom{;}12x^{2}-10x\phantom{;}-12\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-3-;x^n;}\underline{-12x^{2}+18x\phantom{;}\phantom{-;x^n}}\\\phantom{;-12x^{2}+18x\phantom{;}-;x^n;}\phantom{;}8x\phantom{;}-12\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-3-;x^n-;x^n;}\underline{-8x\phantom{;}+12\phantom{;}\phantom{;}}\\\phantom{;;-8x\phantom{;}+12\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$3x^{2}+6x+4$