Esercizio
$\frac{\left(x^4+3x^3-28x^2+6x-15\right)}{\left(x-4\right)}$
Soluzione passo-passo
1
Dividere $x^4+3x^3-28x^2+6x-15$ per $x-4$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-4;}{\phantom{;}x^{3}+7x^{2}\phantom{-;x^n}+6\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-4\overline{\smash{)}\phantom{;}x^{4}+3x^{3}-28x^{2}+6x\phantom{;}-15\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-4;}\underline{-x^{4}+4x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}+4x^{3};}\phantom{;}7x^{3}-28x^{2}+6x\phantom{;}-15\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-4-;x^n;}\underline{-7x^{3}+28x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-7x^{3}+28x^{2}-;x^n;}\phantom{;}6x\phantom{;}-15\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-4-;x^n-;x^n;}\underline{-6x\phantom{;}+24\phantom{;}\phantom{;}}\\\phantom{;;-6x\phantom{;}+24\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}9\phantom{;}\phantom{;}\\\end{array}$
$x^{3}+7x^{2}+6+\frac{9}{x-4}$
Risposta finale al problema
$x^{3}+7x^{2}+6+\frac{9}{x-4}$