Esercizio
$\frac{\left(x^4-2x^3+3x^2-2x+8\right)}{\left(x^2-3x+4\right)}$
Soluzione passo-passo
1
Dividere $x^4-2x^3+3x^2-2x+8$ per $x^2-3x+4$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-3x\phantom{;}+4;}{\phantom{;}x^{2}+x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-3x\phantom{;}+4\overline{\smash{)}\phantom{;}x^{4}-2x^{3}+3x^{2}-2x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-3x\phantom{;}+4;}\underline{-x^{4}+3x^{3}-4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}+3x^{3}-4x^{2};}\phantom{;}x^{3}-x^{2}-2x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3x\phantom{;}+4-;x^n;}\underline{-x^{3}+3x^{2}-4x\phantom{;}\phantom{-;x^n}}\\\phantom{;-x^{3}+3x^{2}-4x\phantom{;}-;x^n;}\phantom{;}2x^{2}-6x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3x\phantom{;}+4-;x^n-;x^n;}\underline{-2x^{2}+6x\phantom{;}-8\phantom{;}\phantom{;}}\\\phantom{;;-2x^{2}+6x\phantom{;}-8\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$x^{2}+x+2$