Impara online a risolvere i problemi di passo dopo passo. (tan(40)^2-tan(20)^2)/(1-tan(40)^2tan(20)^2). Applicare l'identità trigonometrica: \tan\left(\theta \right)^n=\frac{\sin\left(\theta \right)^n}{\cos\left(\theta \right)^n}, dove x=40 e n=2. Riscrivere 1- \tan\left(40\right)^2\cdot \tan\left(20\right)^2 in termini di funzioni seno e coseno.. Applicare la formula: a+\frac{b}{c}=\frac{b+ac}{c}, dove a=1, b=- \sin\left(40\right)^2\cdot \sin\left(20\right)^2, c=\cos\left(40\right)^2\cdot \cos\left(20\right)^2, a+b/c=1+\frac{- \sin\left(40\right)^2\cdot \sin\left(20\right)^2}{\cos\left(40\right)^2\cdot \cos\left(20\right)^2} e b/c=\frac{- \sin\left(40\right)^2\cdot \sin\left(20\right)^2}{\cos\left(40\right)^2\cdot \cos\left(20\right)^2}. Applicare la formula: \frac{a}{\frac{b}{c}}=\frac{ac}{b}, dove a=\frac{\sin\left(40\right)^2}{\cos\left(40\right)^2}- \tan\left(20\right)^2, b=- \sin\left(40\right)^2\cdot \sin\left(20\right)^2+\cos\left(40\right)^2\cdot \cos\left(20\right)^2, c=\cos\left(40\right)^2\cdot \cos\left(20\right)^2, a/b/c=\frac{\frac{\sin\left(40\right)^2}{\cos\left(40\right)^2}- \tan\left(20\right)^2}{\frac{- \sin\left(40\right)^2\cdot \sin\left(20\right)^2+\cos\left(40\right)^2\cdot \cos\left(20\right)^2}{\cos\left(40\right)^2\cdot \cos\left(20\right)^2}} e b/c=\frac{- \sin\left(40\right)^2\cdot \sin\left(20\right)^2+\cos\left(40\right)^2\cdot \cos\left(20\right)^2}{\cos\left(40\right)^2\cdot \cos\left(20\right)^2}.

(tan(40)^2-tan(20)^2)/(1-tan(40)^2tan(20)^2)