Impara online a risolvere i problemi di passo dopo passo. (tan(33)+tan(27))/(1-tan(33)tan(27)). Applicare l'identità trigonometrica: \tan\left(\theta \right)=\frac{\sin\left(\theta \right)}{\cos\left(\theta \right)}, dove x=27. Applicare la formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, dove a=-\sin\left(33\right), b=\cos\left(33\right), c=\sin\left(27\right), a/b=\frac{-\sin\left(33\right)}{\cos\left(33\right)}, f=\cos\left(27\right), c/f=\frac{\sin\left(27\right)}{\cos\left(27\right)} e a/bc/f=\frac{-\sin\left(33\right)}{\cos\left(33\right)}\cdot \frac{\sin\left(27\right)}{\cos\left(27\right)}. Applicare la formula: a+\frac{b}{c}=\frac{b+ac}{c}, dove a=1, b=-\sin\left(33\right)\sin\left(27\right), c=\cos\left(33\right)\cos\left(27\right), a+b/c=1+\frac{-\sin\left(33\right)\sin\left(27\right)}{\cos\left(33\right)\cos\left(27\right)} e b/c=\frac{-\sin\left(33\right)\sin\left(27\right)}{\cos\left(33\right)\cos\left(27\right)}. Applicare la formula: \frac{a}{\frac{b}{c}}=\frac{ac}{b}, dove a=\frac{\sin\left(33\right)}{\cos\left(33\right)}+\frac{\sin\left(27\right)}{\cos\left(27\right)}, b=-\sin\left(33\right)\sin\left(27\right)+\cos\left(33\right)\cos\left(27\right), c=\cos\left(33\right)\cos\left(27\right), a/b/c=\frac{\frac{\sin\left(33\right)}{\cos\left(33\right)}+\frac{\sin\left(27\right)}{\cos\left(27\right)}}{\frac{-\sin\left(33\right)\sin\left(27\right)+\cos\left(33\right)\cos\left(27\right)}{\cos\left(33\right)\cos\left(27\right)}} e b/c=\frac{-\sin\left(33\right)\sin\left(27\right)+\cos\left(33\right)\cos\left(27\right)}{\cos\left(33\right)\cos\left(27\right)}.

(tan(33)+tan(27))/(1-tan(33)tan(27))