Impara online a risolvere i problemi di integrali di funzioni esponenziali passo dopo passo. (tan(5x)-tan(3y))/(1+tan(5x)tan(3y)). Applicare l'identità trigonometrica: \tan\left(\theta \right)=\frac{\sin\left(\theta \right)}{\cos\left(\theta \right)}, dove x=3y. Applicare la formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, dove a=\sin\left(5x\right), b=\cos\left(5x\right), c=\sin\left(3y\right), a/b=\frac{\sin\left(5x\right)}{\cos\left(5x\right)}, f=\cos\left(3y\right), c/f=\frac{\sin\left(3y\right)}{\cos\left(3y\right)} e a/bc/f=\frac{\sin\left(5x\right)}{\cos\left(5x\right)}\frac{\sin\left(3y\right)}{\cos\left(3y\right)}. Applicare la formula: a+\frac{b}{c}=\frac{b+ac}{c}, dove a=1, b=\sin\left(5x\right)\sin\left(3y\right), c=\cos\left(5x\right)\cos\left(3y\right), a+b/c=1+\frac{\sin\left(5x\right)\sin\left(3y\right)}{\cos\left(5x\right)\cos\left(3y\right)} e b/c=\frac{\sin\left(5x\right)\sin\left(3y\right)}{\cos\left(5x\right)\cos\left(3y\right)}. Applicare la formula: \frac{a}{\frac{b}{c}}=\frac{ac}{b}, dove a=\frac{\sin\left(5x\right)}{\cos\left(5x\right)}+\frac{-\sin\left(3y\right)}{\cos\left(3y\right)}, b=\sin\left(5x\right)\sin\left(3y\right)+\cos\left(5x\right)\cos\left(3y\right), c=\cos\left(5x\right)\cos\left(3y\right), a/b/c=\frac{\frac{\sin\left(5x\right)}{\cos\left(5x\right)}+\frac{-\sin\left(3y\right)}{\cos\left(3y\right)}}{\frac{\sin\left(5x\right)\sin\left(3y\right)+\cos\left(5x\right)\cos\left(3y\right)}{\cos\left(5x\right)\cos\left(3y\right)}} e b/c=\frac{\sin\left(5x\right)\sin\left(3y\right)+\cos\left(5x\right)\cos\left(3y\right)}{\cos\left(5x\right)\cos\left(3y\right)}.

(tan(5x)-tan(3y))/(1+tan(5x)tan(3y))