Esercizio
$\frac{-4x+7x^2+6x^3-3}{2x+1}$
Soluzione passo-passo
1
Dividere $-4x+7x^2+6x^3-3$ per $2x+1$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+1;}{\phantom{;}3x^{2}+2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+1\overline{\smash{)}\phantom{;}6x^{3}+7x^{2}-4x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+1;}\underline{-6x^{3}-3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-6x^{3}-3x^{2};}\phantom{;}4x^{2}-4x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+1-;x^n;}\underline{-4x^{2}-2x\phantom{;}\phantom{-;x^n}}\\\phantom{;-4x^{2}-2x\phantom{;}-;x^n;}-6x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+1-;x^n-;x^n;}\underline{\phantom{;}6x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}6x\phantom{;}+3\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$3x^{2}+2x-3$