Esercizio
$\frac{-4x^4+20x^3-24x^2-2}{-2x^2+2x+1}$
Soluzione passo-passo
1
Dividere $-4x^4+20x^3-24x^2-2$ per $-2x^2+2x+1$
$\begin{array}{l}\phantom{-2x^{2}+2x\phantom{;}+1;}{\phantom{;}2x^{2}-8x\phantom{;}+5\phantom{;}\phantom{;}}\\-2x^{2}+2x\phantom{;}+1\overline{\smash{)}-4x^{4}+20x^{3}-24x^{2}\phantom{-;x^n}-2\phantom{;}\phantom{;}}\\\phantom{-2x^{2}+2x\phantom{;}+1;}\underline{\phantom{;}4x^{4}-4x^{3}-2x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}4x^{4}-4x^{3}-2x^{2};}\phantom{;}16x^{3}-26x^{2}\phantom{-;x^n}-2\phantom{;}\phantom{;}\\\phantom{-2x^{2}+2x\phantom{;}+1-;x^n;}\underline{-16x^{3}+16x^{2}+8x\phantom{;}\phantom{-;x^n}}\\\phantom{;-16x^{3}+16x^{2}+8x\phantom{;}-;x^n;}-10x^{2}+8x\phantom{;}-2\phantom{;}\phantom{;}\\\phantom{-2x^{2}+2x\phantom{;}+1-;x^n-;x^n;}\underline{\phantom{;}10x^{2}-10x\phantom{;}-5\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}10x^{2}-10x\phantom{;}-5\phantom{;}\phantom{;}-;x^n-;x^n;}-2x\phantom{;}-7\phantom{;}\phantom{;}\\\end{array}$
$2x^{2}-8x+5+\frac{-2x-7}{-2x^2+2x+1}$
Risposta finale al problema
$2x^{2}-8x+5+\frac{-2x-7}{-2x^2+2x+1}$