Esercizio
$\frac{-9x^2+x^4+x-3}{x+3}$
Soluzione passo-passo
1
Dividere $-9x^2+x^4+x-3$ per $x+3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+3;}{\phantom{;}x^{3}-3x^{2}\phantom{-;x^n}+1\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+3\overline{\smash{)}\phantom{;}x^{4}\phantom{-;x^n}-9x^{2}+x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+3;}\underline{-x^{4}-3x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}-3x^{3};}-3x^{3}-9x^{2}+x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n;}\underline{\phantom{;}3x^{3}+9x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{3}+9x^{2}-;x^n;}\phantom{;}x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n;}\underline{-x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;;-x\phantom{;}-3\phantom{;}\phantom{;}-;x^n-;x^n;}-6\phantom{;}\phantom{;}\\\end{array}$
$x^{3}-3x^{2}+1+\frac{-6}{x+3}$
Risposta finale al problema
$x^{3}-3x^{2}+1+\frac{-6}{x+3}$