Esercizio
$\frac{1+\sin\left(b\right)}{1-\sin\left(b\right)}$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. (1+sin(b))/(1-sin(b)). Applicare la formula: \frac{a}{b}=\frac{a}{b}\frac{conjugate\left(b\right)}{conjugate\left(b\right)}, dove a=1+\sin\left(b\right), b=1-\sin\left(b\right) e a/b=\frac{1+\sin\left(b\right)}{1-\sin\left(b\right)}. Applicare la formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, dove a=1+\sin\left(b\right), b=1-\sin\left(b\right), c=1+\sin\left(b\right), a/b=\frac{1+\sin\left(b\right)}{1-\sin\left(b\right)}, f=1+\sin\left(b\right), c/f=\frac{1+\sin\left(b\right)}{1+\sin\left(b\right)} e a/bc/f=\frac{1+\sin\left(b\right)}{1-\sin\left(b\right)}\frac{1+\sin\left(b\right)}{1+\sin\left(b\right)}. Applicare la formula: x\cdot x=x^2, dove x=1+\sin\left(b\right). Applicare la formula: \left(a+b\right)\left(a+c\right)=a^2-b^2, dove a=1, b=\sin\left(b\right), c=-\sin\left(b\right), a+c=1+\sin\left(b\right) e a+b=1-\sin\left(b\right).
Risposta finale al problema
$\frac{1+2\sin\left(b\right)+\sin\left(b\right)^2}{\cos\left(b\right)^2}$