Esercizio
$\frac{16x^4-24x^3+28x^2-5}{2x-1}$
Soluzione passo-passo
1
Dividere $16x^4-24x^3+28x^2-5$ per $2x-1$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-1;}{\phantom{;}8x^{3}-8x^{2}+10x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-1\overline{\smash{)}\phantom{;}16x^{4}-24x^{3}+28x^{2}\phantom{-;x^n}-5\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-1;}\underline{-16x^{4}+8x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-16x^{4}+8x^{3};}-16x^{3}+28x^{2}\phantom{-;x^n}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n;}\underline{\phantom{;}16x^{3}-8x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}16x^{3}-8x^{2}-;x^n;}\phantom{;}20x^{2}\phantom{-;x^n}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n-;x^n;}\underline{-20x^{2}+10x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-20x^{2}+10x\phantom{;}-;x^n-;x^n;}\phantom{;}10x\phantom{;}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n-;x^n-;x^n;}\underline{-10x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{;;;-10x\phantom{;}+5\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\\\end{array}$
$8x^{3}-8x^{2}+10x+5$
Risposta finale al problema
$8x^{3}-8x^{2}+10x+5$