Esercizio
$\frac{2x^2-15}{x+4}$
Soluzione passo-passo
1
Dividere $2x^2-15$ per $x+4$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+4;}{\phantom{;}2x\phantom{;}-8\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+4\overline{\smash{)}\phantom{;}2x^{2}\phantom{-;x^n}-15\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+4;}\underline{-2x^{2}-8x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{2}-8x\phantom{;};}-8x\phantom{;}-15\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+4-;x^n;}\underline{\phantom{;}8x\phantom{;}+32\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}8x\phantom{;}+32\phantom{;}\phantom{;}-;x^n;}\phantom{;}17\phantom{;}\phantom{;}\\\end{array}$
$2x-8+\frac{17}{x+4}$
Risposta finale al problema
$2x-8+\frac{17}{x+4}$