Esercizio
$\frac{2x^3+4x^2-x-4}{x+3}$
Soluzione passo-passo
1
Dividere $2x^3+4x^2-x-4$ per $x+3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+3;}{\phantom{;}2x^{2}-2x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+3\overline{\smash{)}\phantom{;}2x^{3}+4x^{2}-x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+3;}\underline{-2x^{3}-6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{3}-6x^{2};}-2x^{2}-x\phantom{;}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n;}\underline{\phantom{;}2x^{2}+6x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}2x^{2}+6x\phantom{;}-;x^n;}\phantom{;}5x\phantom{;}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n;}\underline{-5x\phantom{;}-15\phantom{;}\phantom{;}}\\\phantom{;;-5x\phantom{;}-15\phantom{;}\phantom{;}-;x^n-;x^n;}-19\phantom{;}\phantom{;}\\\end{array}$
$2x^{2}-2x+5+\frac{-19}{x+3}$
Risposta finale al problema
$2x^{2}-2x+5+\frac{-19}{x+3}$