Esercizio
$\frac{2x^3-6x^2+x-1}{2x^2+1}$
Soluzione passo-passo
1
Dividere $2x^3-6x^2+x-1$ per $2x^2+1$
$\begin{array}{l}\phantom{\phantom{;}2x^{2}+1;}{\phantom{;}x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x^{2}+1\overline{\smash{)}\phantom{;}2x^{3}-6x^{2}+x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x^{2}+1;}\underline{-2x^{3}\phantom{-;x^n}-x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{3}-x\phantom{;};}-6x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x^{2}+1-;x^n;}\underline{\phantom{;}6x^{2}\phantom{-;x^n}+3\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}6x^{2}+3\phantom{;}\phantom{;}-;x^n;}\phantom{;}2\phantom{;}\phantom{;}\\\end{array}$
$x-3+\frac{2}{2x^2+1}$
Risposta finale al problema
$x-3+\frac{2}{2x^2+1}$