Esercizio
$\frac{2x^4+5x^3-2x-8}{x+3}$
Soluzione passo-passo
1
Dividere $2x^4+5x^3-2x-8$ per $x+3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+3;}{\phantom{;}2x^{3}-x^{2}+3x\phantom{;}-11\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+3\overline{\smash{)}\phantom{;}2x^{4}+5x^{3}\phantom{-;x^n}-2x\phantom{;}-8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+3;}\underline{-2x^{4}-6x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}-6x^{3};}-x^{3}\phantom{-;x^n}-2x\phantom{;}-8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n;}\underline{\phantom{;}x^{3}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}x^{3}+3x^{2}-;x^n;}\phantom{;}3x^{2}-2x\phantom{;}-8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n;}\underline{-3x^{2}-9x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-3x^{2}-9x\phantom{;}-;x^n-;x^n;}-11x\phantom{;}-8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n-;x^n;}\underline{\phantom{;}11x\phantom{;}+33\phantom{;}\phantom{;}}\\\phantom{;;;\phantom{;}11x\phantom{;}+33\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}25\phantom{;}\phantom{;}\\\end{array}$
$2x^{3}-x^{2}+3x-11+\frac{25}{x+3}$
Risposta finale al problema
$2x^{3}-x^{2}+3x-11+\frac{25}{x+3}$