Esercizio
$\frac{2x^4-3x+2}{x-2}$
Soluzione passo-passo
1
Dividere $2x^4-3x+2$ per $x-2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-2;}{\phantom{;}2x^{3}+4x^{2}+8x\phantom{;}+13\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-2\overline{\smash{)}\phantom{;}2x^{4}\phantom{-;x^n}\phantom{-;x^n}-3x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-2;}\underline{-2x^{4}+4x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}+4x^{3};}\phantom{;}4x^{3}\phantom{-;x^n}-3x\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n;}\underline{-4x^{3}+8x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-4x^{3}+8x^{2}-;x^n;}\phantom{;}8x^{2}-3x\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n;}\underline{-8x^{2}+16x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-8x^{2}+16x\phantom{;}-;x^n-;x^n;}\phantom{;}13x\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n-;x^n;}\underline{-13x\phantom{;}+26\phantom{;}\phantom{;}}\\\phantom{;;;-13x\phantom{;}+26\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}28\phantom{;}\phantom{;}\\\end{array}$
$2x^{3}+4x^{2}+8x+13+\frac{28}{x-2}$
Risposta finale al problema
$2x^{3}+4x^{2}+8x+13+\frac{28}{x-2}$