Esercizio
$\frac{2x^4-7x^3+7x^2-13}{x-2}$
Soluzione passo-passo
1
Dividere $2x^4-7x^3+7x^2-13$ per $x-2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-2;}{\phantom{;}2x^{3}-3x^{2}+x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-2\overline{\smash{)}\phantom{;}2x^{4}-7x^{3}+7x^{2}\phantom{-;x^n}-13\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-2;}\underline{-2x^{4}+4x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}+4x^{3};}-3x^{3}+7x^{2}\phantom{-;x^n}-13\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n;}\underline{\phantom{;}3x^{3}-6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{3}-6x^{2}-;x^n;}\phantom{;}x^{2}\phantom{-;x^n}-13\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n;}\underline{-x^{2}+2x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-x^{2}+2x\phantom{;}-;x^n-;x^n;}\phantom{;}2x\phantom{;}-13\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n-;x^n;}\underline{-2x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{;;;-2x\phantom{;}+4\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}-9\phantom{;}\phantom{;}\\\end{array}$
$2x^{3}-3x^{2}+x+2+\frac{-9}{x-2}$
Risposta finale al problema
$2x^{3}-3x^{2}+x+2+\frac{-9}{x-2}$