Esercizio
$\frac{2x^4-7x^3-14x+8}{x-4}$
Soluzione passo-passo
1
Dividere $2x^4-7x^3-14x+8$ per $x-4$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-4;}{\phantom{;}2x^{3}+x^{2}+4x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-4\overline{\smash{)}\phantom{;}2x^{4}-7x^{3}\phantom{-;x^n}-14x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-4;}\underline{-2x^{4}+8x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}+8x^{3};}\phantom{;}x^{3}\phantom{-;x^n}-14x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-4-;x^n;}\underline{-x^{3}+4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-x^{3}+4x^{2}-;x^n;}\phantom{;}4x^{2}-14x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-4-;x^n-;x^n;}\underline{-4x^{2}+16x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-4x^{2}+16x\phantom{;}-;x^n-;x^n;}\phantom{;}2x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-4-;x^n-;x^n-;x^n;}\underline{-2x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{;;;-2x\phantom{;}+8\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}16\phantom{;}\phantom{;}\\\end{array}$
$2x^{3}+x^{2}+4x+2+\frac{16}{x-4}$
Risposta finale al problema
$2x^{3}+x^{2}+4x+2+\frac{16}{x-4}$