Esercizio
$\frac{2x^4-x^3-3x^2+7x+12}{x^2-3}$
Soluzione passo-passo
1
Dividere $2x^4-x^3-3x^2+7x+12$ per $x^2-3$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-3;}{\phantom{;}2x^{2}-x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-3\overline{\smash{)}\phantom{;}2x^{4}-x^{3}-3x^{2}+7x\phantom{;}+12\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-3;}\underline{-2x^{4}\phantom{-;x^n}+6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}+6x^{2};}-x^{3}+3x^{2}+7x\phantom{;}+12\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3-;x^n;}\underline{\phantom{;}x^{3}\phantom{-;x^n}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}x^{3}-3x\phantom{;}-;x^n;}\phantom{;}3x^{2}+4x\phantom{;}+12\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3-;x^n-;x^n;}\underline{-3x^{2}\phantom{-;x^n}+9\phantom{;}\phantom{;}}\\\phantom{;;-3x^{2}+9\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}4x\phantom{;}+21\phantom{;}\phantom{;}\\\end{array}$
$2x^{2}-x+3+\frac{4x+21}{x^2-3}$
Risposta finale al problema
$2x^{2}-x+3+\frac{4x+21}{x^2-3}$