Esercizio
$\frac{3a^4+5a^3-2a+3}{a^2+3}$
Soluzione passo-passo
1
Dividere $3a^4+5a^3-2a+3$ per $a^2+3$
$\begin{array}{l}\phantom{\phantom{;}a^{2}+3;}{\phantom{;}3a^{2}+5a\phantom{;}-9\phantom{;}\phantom{;}}\\\phantom{;}a^{2}+3\overline{\smash{)}\phantom{;}3a^{4}+5a^{3}\phantom{-;x^n}-2a\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}a^{2}+3;}\underline{-3a^{4}\phantom{-;x^n}-9a^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3a^{4}-9a^{2};}\phantom{;}5a^{3}-9a^{2}-2a\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}a^{2}+3-;x^n;}\underline{-5a^{3}\phantom{-;x^n}-15a\phantom{;}\phantom{-;x^n}}\\\phantom{;-5a^{3}-15a\phantom{;}-;x^n;}-9a^{2}-17a\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}a^{2}+3-;x^n-;x^n;}\underline{\phantom{;}9a^{2}\phantom{-;x^n}+27\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}9a^{2}+27\phantom{;}\phantom{;}-;x^n-;x^n;}-17a\phantom{;}+30\phantom{;}\phantom{;}\\\end{array}$
$3a^{2}+5a-9+\frac{-17a+30}{a^2+3}$
Risposta finale al problema
$3a^{2}+5a-9+\frac{-17a+30}{a^2+3}$