Esercizio
$\frac{3x^2}{1-2x}$
Soluzione passo-passo
1
Dividere $3x^2$ per $1-2x$
$\begin{array}{l}\phantom{-2x\phantom{;}+1;}{\frac{3}{-2}x\phantom{;}+\frac{1.5}{-2}\phantom{;}\phantom{;}}\\-2x\phantom{;}+1\overline{\smash{)}\phantom{;}3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x\phantom{;}+1;}\underline{-3x^{2}+1.5x\phantom{;}\phantom{-;x^n}}\\\phantom{-3x^{2}+1.5x\phantom{;};}\phantom{;}1.5x\phantom{;}\phantom{-;x^n}\\\phantom{-2x\phantom{;}+1-;x^n;}\underline{-1.5x\phantom{;}+0.75\phantom{;}\phantom{;}}\\\phantom{;-1.5x\phantom{;}+0.75\phantom{;}\phantom{;}-;x^n;}\phantom{;}0.75\phantom{;}\phantom{;}\\\end{array}$
$\frac{3}{-2}x+\frac{1.5}{-2}+\frac{0.75}{1-2x}$
Risposta finale al problema
$\frac{3}{-2}x+\frac{1.5}{-2}+\frac{0.75}{1-2x}$