Esercizio
$\frac{4x^3+12x^2+23x+21}{2x+3}$
Soluzione passo-passo
1
Dividere $4x^3+12x^2+23x+21$ per $2x+3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+3;}{\phantom{;}2x^{2}+3x\phantom{;}+7\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+3\overline{\smash{)}\phantom{;}4x^{3}+12x^{2}+23x\phantom{;}+21\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+3;}\underline{-4x^{3}-6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-4x^{3}-6x^{2};}\phantom{;}6x^{2}+23x\phantom{;}+21\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n;}\underline{-6x^{2}-9x\phantom{;}\phantom{-;x^n}}\\\phantom{;-6x^{2}-9x\phantom{;}-;x^n;}\phantom{;}14x\phantom{;}+21\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n-;x^n;}\underline{-14x\phantom{;}-21\phantom{;}\phantom{;}}\\\phantom{;;-14x\phantom{;}-21\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$2x^{2}+3x+7$