Esercizio
$\frac{4x^4-2x^2-1}{x+2}$
Soluzione passo-passo
1
Dividere $4x^4-2x^2-1$ per $x+2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+2;}{\phantom{;}4x^{3}-8x^{2}+14x\phantom{;}-28\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+2\overline{\smash{)}\phantom{;}4x^{4}\phantom{-;x^n}-2x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+2;}\underline{-4x^{4}-8x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-4x^{4}-8x^{3};}-8x^{3}-2x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n;}\underline{\phantom{;}8x^{3}+16x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}8x^{3}+16x^{2}-;x^n;}\phantom{;}14x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n-;x^n;}\underline{-14x^{2}-28x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-14x^{2}-28x\phantom{;}-;x^n-;x^n;}-28x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n-;x^n-;x^n;}\underline{\phantom{;}28x\phantom{;}+56\phantom{;}\phantom{;}}\\\phantom{;;;\phantom{;}28x\phantom{;}+56\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}55\phantom{;}\phantom{;}\\\end{array}$
$4x^{3}-8x^{2}+14x-28+\frac{55}{x+2}$
Risposta finale al problema
$4x^{3}-8x^{2}+14x-28+\frac{55}{x+2}$