Esercizio
$\frac{5x^2-38x+16}{x-7}$
Soluzione passo-passo
1
Dividere $5x^2-38x+16$ per $x-7$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-7;}{\phantom{;}5x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-7\overline{\smash{)}\phantom{;}5x^{2}-38x\phantom{;}+16\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-7;}\underline{-5x^{2}+35x\phantom{;}\phantom{-;x^n}}\\\phantom{-5x^{2}+35x\phantom{;};}-3x\phantom{;}+16\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-7-;x^n;}\underline{\phantom{;}3x\phantom{;}-21\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}3x\phantom{;}-21\phantom{;}\phantom{;}-;x^n;}-5\phantom{;}\phantom{;}\\\end{array}$
$5x-3+\frac{-5}{x-7}$
Risposta finale al problema
$5x-3+\frac{-5}{x-7}$