Esercizio
$\frac{5x^3-4x-6}{x+1}$
Soluzione passo-passo
1
Dividere $5x^3-4x-6$ per $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}5x^{2}-5x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}5x^{3}\phantom{-;x^n}-4x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-5x^{3}-5x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-5x^{3}-5x^{2};}-5x^{2}-4x\phantom{;}-6\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}5x^{2}+5x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}5x^{2}+5x\phantom{;}-;x^n;}\phantom{;}x\phantom{;}-6\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n;}\underline{-x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{;;-x\phantom{;}-1\phantom{;}\phantom{;}-;x^n-;x^n;}-7\phantom{;}\phantom{;}\\\end{array}$
$5x^{2}-5x+1+\frac{-7}{x+1}$
Risposta finale al problema
$5x^{2}-5x+1+\frac{-7}{x+1}$