Esercizio
$\frac{6x^3+18x^2-2x+5}{3x^2-4}$
Soluzione passo-passo
1
Dividere $6x^3+18x^2-2x+5$ per $3x^2-4$
$\begin{array}{l}\phantom{\phantom{;}3x^{2}-4;}{\phantom{;}2x\phantom{;}+6\phantom{;}\phantom{;}}\\\phantom{;}3x^{2}-4\overline{\smash{)}\phantom{;}6x^{3}+18x^{2}-2x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{\phantom{;}3x^{2}-4;}\underline{-6x^{3}\phantom{-;x^n}+8x\phantom{;}\phantom{-;x^n}}\\\phantom{-6x^{3}+8x\phantom{;};}\phantom{;}18x^{2}+6x\phantom{;}+5\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x^{2}-4-;x^n;}\underline{-18x^{2}\phantom{-;x^n}+24\phantom{;}\phantom{;}}\\\phantom{;-18x^{2}+24\phantom{;}\phantom{;}-;x^n;}\phantom{;}6x\phantom{;}+29\phantom{;}\phantom{;}\\\end{array}$
$2x+6+\frac{6x+29}{3x^2-4}$
Risposta finale al problema
$2x+6+\frac{6x+29}{3x^2-4}$