Esercizio
$\frac{6x^3-17x^2+16}{3x-4}$
Soluzione passo-passo
1
Dividere $6x^3-17x^2+16$ per $3x-4$
$\begin{array}{l}\phantom{\phantom{;}3x\phantom{;}-4;}{\phantom{;}2x^{2}-3x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{;}3x\phantom{;}-4\overline{\smash{)}\phantom{;}6x^{3}-17x^{2}\phantom{-;x^n}+16\phantom{;}\phantom{;}}\\\phantom{\phantom{;}3x\phantom{;}-4;}\underline{-6x^{3}+8x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-6x^{3}+8x^{2};}-9x^{2}\phantom{-;x^n}+16\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-4-;x^n;}\underline{\phantom{;}9x^{2}-12x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}9x^{2}-12x\phantom{;}-;x^n;}-12x\phantom{;}+16\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-4-;x^n-;x^n;}\underline{\phantom{;}12x\phantom{;}-16\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}12x\phantom{;}-16\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$2x^{2}-3x-4$