Esercizio
$\frac{6x^3-7x^2+4x-3}{2x-1}$
Soluzione passo-passo
1
Dividere $6x^3-7x^2+4x-3$ per $2x-1$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-1;}{\phantom{;}3x^{2}-2x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-1\overline{\smash{)}\phantom{;}6x^{3}-7x^{2}+4x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-1;}\underline{-6x^{3}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-6x^{3}+3x^{2};}-4x^{2}+4x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n;}\underline{\phantom{;}4x^{2}-2x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}4x^{2}-2x\phantom{;}-;x^n;}\phantom{;}2x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n-;x^n;}\underline{-2x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;;-2x\phantom{;}+1\phantom{;}\phantom{;}-;x^n-;x^n;}-2\phantom{;}\phantom{;}\\\end{array}$
$3x^{2}-2x+1+\frac{-2}{2x-1}$
Risposta finale al problema
$3x^{2}-2x+1+\frac{-2}{2x-1}$