Esercizio
$\frac{7z^4-14z^3+38z^2-32z-25}{z^2-z+5}$
Soluzione passo-passo
1
Dividere $7z^4-14z^3+38z^2-32z-25$ per $z^2-z+5$
$\begin{array}{l}\phantom{\phantom{;}z^{2}-z\phantom{;}+5;}{\phantom{;}7z^{2}-7z\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{;}z^{2}-z\phantom{;}+5\overline{\smash{)}\phantom{;}7z^{4}-14z^{3}+38z^{2}-32z\phantom{;}-25\phantom{;}\phantom{;}}\\\phantom{\phantom{;}z^{2}-z\phantom{;}+5;}\underline{-7z^{4}+7z^{3}-35z^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-7z^{4}+7z^{3}-35z^{2};}-7z^{3}+3z^{2}-32z\phantom{;}-25\phantom{;}\phantom{;}\\\phantom{\phantom{;}z^{2}-z\phantom{;}+5-;x^n;}\underline{\phantom{;}7z^{3}-7z^{2}+35z\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}7z^{3}-7z^{2}+35z\phantom{;}-;x^n;}-4z^{2}+3z\phantom{;}-25\phantom{;}\phantom{;}\\\phantom{\phantom{;}z^{2}-z\phantom{;}+5-;x^n-;x^n;}\underline{\phantom{;}4z^{2}-4z\phantom{;}+20\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}4z^{2}-4z\phantom{;}+20\phantom{;}\phantom{;}-;x^n-;x^n;}-z\phantom{;}-5\phantom{;}\phantom{;}\\\end{array}$
$7z^{2}-7z-4+\frac{-z-5}{z^2-z+5}$
Risposta finale al problema
$7z^{2}-7z-4+\frac{-z-5}{z^2-z+5}$