Esercizio
$\frac{8x^3+6x^2-3x-1}{2x-1}$
Soluzione passo-passo
1
Dividere $8x^3+6x^2-3x-1$ per $2x-1$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-1;}{\phantom{;}4x^{2}+5x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-1\overline{\smash{)}\phantom{;}8x^{3}+6x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-1;}\underline{-8x^{3}+4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-8x^{3}+4x^{2};}\phantom{;}10x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n;}\underline{-10x^{2}+5x\phantom{;}\phantom{-;x^n}}\\\phantom{;-10x^{2}+5x\phantom{;}-;x^n;}\phantom{;}2x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n-;x^n;}\underline{-2x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;;-2x\phantom{;}+1\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$4x^{2}+5x+1$