Impara online a risolvere i problemi di prodotti speciali passo dopo passo. d/dt((t/(9t+1))^(1/6)). Applicare la formula: \frac{d}{dx}\left(x^a\right)=ax^{\left(a-1\right)}\frac{d}{dx}\left(x\right), dove a=\frac{1}{6} e x=\frac{t}{9t+1}. Applicare la formula: \left(\frac{a}{b}\right)^n=\left(\frac{b}{a}\right)^{\left|n\right|}, dove a=t, b=9t+1 e n=-\frac{5}{6}. Applicare la formula: \frac{d}{dx}\left(\frac{a}{b}\right)=\frac{\frac{d}{dx}\left(a\right)b-a\frac{d}{dx}\left(b\right)}{b^2}, dove a=t e b=9t+1. Applicare la formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, dove a=1, b=6, c=\frac{d}{dt}\left(t\right)\left(9t+1\right)-t\frac{d}{dt}\left(9t+1\right), a/b=\frac{1}{6}, f=\left(9t+1\right)^2, c/f=\frac{\frac{d}{dt}\left(t\right)\left(9t+1\right)-t\frac{d}{dt}\left(9t+1\right)}{\left(9t+1\right)^2} e a/bc/f=\frac{1}{6}\sqrt[6]{\left(\frac{9t+1}{t}\right)^{5}}\frac{\frac{d}{dt}\left(t\right)\left(9t+1\right)-t\frac{d}{dt}\left(9t+1\right)}{\left(9t+1\right)^2}.

d/dt((t/(9t+1))^(1/6))