Impara online a risolvere i problemi di passo dopo passo. Find the derivative d/dx((2x^2+x+1)/(3x^2-x+-1)). Applicare la formula: \frac{d}{dx}\left(x\right)=y=x, dove d/dx=\frac{d}{dx}, d/dx?x=\frac{d}{dx}\left(\frac{2x^2+x+1}{3x^2-x-1}\right) e x=\frac{2x^2+x+1}{3x^2-x-1}. Applicare la formula: y=x\to \ln\left(y\right)=\ln\left(x\right), dove x=\frac{2x^2+x+1}{3x^2-x-1}. Applicare la formula: y=x\to y=x, dove x=\ln\left(\frac{2x^2+x+1}{3x^2-x-1}\right) e y=\ln\left(y\right). Applicare la formula: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), dove x=\ln\left(2x^2+x+1\right)-\ln\left(3x^2-x-1\right).

Find the derivative d/dx((2x^2+x+1)/(3x^2-x+-1))