$\frac{d}{dx}\left(\arccos\left(\sqrt{1-x^2}\right)\right)$

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Final answer to the problem

$\frac{1}{\sqrt{1-x^2}}$
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Step-by-step Solution

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Apply the formula: $\frac{d}{dx}\left(\arccos\left(\theta \right)\right)$$=\frac{-1}{\sqrt{1-\theta ^2}}\frac{d}{dx}\left(\theta \right)$, where $x=\sqrt{1-x^2}$

$\frac{-1}{\sqrt{1-\left(\sqrt{1-x^2}\right)^2}}\frac{d}{dx}\left(\sqrt{1-x^2}\right)$

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$\frac{-1}{\sqrt{1-\left(\sqrt{1-x^2}\right)^2}}\frac{d}{dx}\left(\sqrt{1-x^2}\right)$

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Learn how to solve problems step by step online. d/dx(arccos((1-x^2)^(1/2))). Apply the formula: \frac{d}{dx}\left(\arccos\left(\theta \right)\right)=\frac{-1}{\sqrt{1-\theta ^2}}\frac{d}{dx}\left(\theta \right), where x=\sqrt{1-x^2}. Apply the formula: \left(x^a\right)^b=x, where a=\frac{1}{2}, b=2, x^a^b=\left(\sqrt{1-x^2}\right)^2, x=1-x^2 and x^a=\sqrt{1-x^2}. Apply the formula: -\left(a+b\right)=-a-b, where a=1, b=-x^2, -1.0=-1 and a+b=1-x^2. Apply the formula: a+b=a+b, where a=1, b=-1 and a+b=1-1+x^2.

Final answer to the problem

$\frac{1}{\sqrt{1-x^2}}$

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Function Plot

Plotting: $\frac{1}{\sqrt{1-x^2}}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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