Esercizio
$\frac{d}{dx}\left(\frac{\left(4x^2-3\right)\left(5x+2\right)}{x\left(3x+1\right)}\right)$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. Find the derivative d/dx(((4x^2-3)(5x+2))/(x(3x+1))). Applicare la formula: \frac{d}{dx}\left(x\right)=y=x, dove d/dx=\frac{d}{dx}, d/dx?x=\frac{d}{dx}\left(\frac{\left(4x^2-3\right)\left(5x+2\right)}{x\left(3x+1\right)}\right) e x=\frac{\left(4x^2-3\right)\left(5x+2\right)}{x\left(3x+1\right)}. Applicare la formula: y=x\to \ln\left(y\right)=\ln\left(x\right), dove x=\frac{\left(4x^2-3\right)\left(5x+2\right)}{x\left(3x+1\right)}. Applicare la formula: y=x\to y=x, dove x=\ln\left(\frac{\left(4x^2-3\right)\left(5x+2\right)}{x\left(3x+1\right)}\right) e y=\ln\left(y\right). Applicare la formula: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), dove x=\ln\left(4x^2-3\right)+\ln\left(5x+2\right)-\ln\left(x\right)-\ln\left(3x+1\right).
Find the derivative d/dx(((4x^2-3)(5x+2))/(x(3x+1)))
Risposta finale al problema
$\left(\frac{8x}{4x^2-3}+\frac{5}{5x+2}+\frac{-1}{x}+\frac{-3}{3x+1}\right)\frac{\left(4x^2-3\right)\left(5x+2\right)}{x\left(3x+1\right)}$