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Apply the formula: $\frac{d}{dx}\left(x\right)$$=y=x$, where $d/dx=\frac{d}{dx}$, $d/dx?x=\frac{d}{dx}\left(\frac{2x^3}{\left(2-5x\right)\sqrt{x^2+1}}\right)$ and $x=\frac{2x^3}{\left(2-5x\right)\sqrt{x^2+1}}$
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$y=\frac{2x^3}{\left(2-5x\right)\sqrt{x^2+1}}$
Learn how to solve problems step by step online. Find the derivative d/dx((2x^3)/((2-5x)(x^2+1)^(1/2))). Apply the formula: \frac{d}{dx}\left(x\right)=y=x, where d/dx=\frac{d}{dx}, d/dx?x=\frac{d}{dx}\left(\frac{2x^3}{\left(2-5x\right)\sqrt{x^2+1}}\right) and x=\frac{2x^3}{\left(2-5x\right)\sqrt{x^2+1}}. Apply the formula: y=x\to \ln\left(y\right)=\ln\left(x\right), where x=\frac{2x^3}{\left(2-5x\right)\sqrt{x^2+1}}. Apply the formula: y=x\to y=x, where x=\ln\left(\frac{2x^3}{\left(2-5x\right)\sqrt{x^2+1}}\right) and y=\ln\left(y\right). Apply the formula: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), where x=\ln\left(2x^3\right)-\ln\left(2-5x\right)-\frac{1}{2}\ln\left(x^2+1\right).
