Impara online a risolvere i problemi di integrali di funzioni razionali passo dopo passo. Find the derivative d/dx((x^3+2x^23x)/(x^2-3x+1)). Applicare la formula: \frac{d}{dx}\left(x\right)=y=x, dove d/dx=\frac{d}{dx}, d/dx?x=\frac{d}{dx}\left(\frac{x^3+2x^2+3x}{x^2-3x+1}\right) e x=\frac{x^3+2x^2+3x}{x^2-3x+1}. Applicare la formula: y=x\to \ln\left(y\right)=\ln\left(x\right), dove x=\frac{x^3+2x^2+3x}{x^2-3x+1}. Applicare la formula: y=x\to y=x, dove x=\ln\left(\frac{x^3+2x^2+3x}{x^2-3x+1}\right) e y=\ln\left(y\right). Applicare la formula: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), dove x=\ln\left(x^3+2x^2+3x\right)-\ln\left(x^2-3x+1\right).

Find the derivative d/dx((x^3+2x^23x)/(x^2-3x+1))