Final answer to the problem
$2x+2y+2xy^{\prime}-2y\cdot y^{\prime}+1=0$
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Step-by-step Solution
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1
Apply the formula: $\frac{d}{dx}\left(a=b\right)$$=\frac{d}{dx}\left(a\right)=\frac{d}{dx}\left(b\right)$, where $a=x^2+2xy-y^2+x$ and $b=2$
$\frac{d}{dx}\left(x^2+2xy-y^2+x\right)=\frac{d}{dx}\left(2\right)$
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$\frac{d}{dx}\left(x^2+2xy-y^2+x\right)=\frac{d}{dx}\left(2\right)$
Learn how to solve problems step by step online. d/dx(x^2+2xy-y^2x=2). Apply the formula: \frac{d}{dx}\left(a=b\right)=\frac{d}{dx}\left(a\right)=\frac{d}{dx}\left(b\right), where a=x^2+2xy-y^2+x and b=2. Apply the formula: \frac{d}{dx}\left(c\right)=0, where c=2. The derivative of a sum of two or more functions is the sum of the derivatives of each function. Apply the formula: \frac{d}{dx}\left(cx\right)=c\frac{d}{dx}\left(x\right).
Final answer to the problem
$2x+2y+2xy^{\prime}-2y\cdot y^{\prime}+1=0$
